how do you find the maximum height of a parbola. How do you find the maximum height of y= 8sinx +2
2007-01-03 17:10:30 · 4 answers · asked by adel q 2 in Science & Mathematics ➔ Mathematics
First, find the maximum of sin x, which is 1. sin x is always between 0 and 1.
So. 8*1+2=10.
The answer is 10.
FYI: y=8sinx+2 is not a parabola. This is a sine function.
A parabola is represented by y=a(x+b)^2+c where the vertiex is at
(-b, c). This point is a maximum when a(x+b)^2 is negative (upside down U) and a minimum if a(x+b)^2 is positive (right side up U).
2007-01-03 17:28:11 · answer #1 · answered by Anonymous · 1⤊ 0⤋
To find the min or max of a function you have to set it equal to zero and choose the answer that makes the most sense in the given situation.
2007-01-04 01:35:58 · answer #2 · answered by Dalonna 2 · 0⤊ 1⤋
A concave-down parabola reaches its maximum at the vertex.
2007-01-04 01:30:17 · answer #3 · answered by arbiter007 6 · 0⤊ 1⤋
the answer is 10.
y=8*1+2
y=8+2
y=10
2007-01-04 01:31:30 · answer #4 · answered by I'm A Shining Star & Im Not Even In Da Sky. 1 · 0⤊ 0⤋