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A line perpendicular to y=3x-2 passes through (0,6) what are the points of the line?

A scatter plot shows a positive correlation which line equation would best fit:

a. y=-5x+1

b. x=16

c. 2x+3y=6

d. y=2x-1

2007-01-03 16:18:42 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

If a line is perpindicular to y=3x-2 it will have a slope of m=-1/3. You know that the equation of a line is y=mx+b. Therefore the equation of the unknown line is 6=(-1/3)(0)+b. Solving you find that b=6. The line is y=-1/3x+6.

A positive correlation means that the slope of the line is positive. Answer a doesn't have a positive slope. Answer b is just a straight line. The answer is either c or d. But my best guess is d.

2007-01-03 16:46:40 · answer #1 · answered by Anonymous · 1 0

A line perpendicular to y=3x-2 passes through (0,6) what are the points of the line?

The slopes of perpendicular lines are negative reciprocals.

The equation of the perpendicular line is:

y - 6 = (-1/3)(x - 0)
y - 6 = -x/3
y = -x/3 + 6

A scatter plot shows a positive correlation which line equation would best fit:

A positive correlation implies a line with a positive slope.

The only line that qualifies is d. The answer is d.

2007-01-03 17:39:38 · answer #2 · answered by Northstar 7 · 0 0

A line perpendicular to y = 3x - 2 passes through (0,6) what are the points of the line?

The perpendicular will have the slope -1/3, so
(y - 6)/(x - 0) = -1/3
3y - 18 = - x
Solving for the intersection,
9x - 6 - 18 = - x
10x = 24
x = 12/5
y = (36 - 24)/5 = 12/5

2007-01-03 17:12:59 · answer #3 · answered by Helmut 7 · 0 0

y=-1/3x-2
y-6=-1/3x
y=-1/3x+6
y=-6(-1/3x+6)
y=2x-1

The answer is d.

2007-01-03 16:58:19 · answer #4 · answered by Anonymous · 0 0

d

2007-01-03 16:39:12 · answer #5 · answered by np200012 2 · 1 0

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