This would give you a rectangular region bounded on two sides by these horizontal and vertical lines, and unbounded on the other two sides. A quarter plane, if you will.
To see why, consider these lines:
x = -1 is a vertical line that goes thru the x axis at -1, and x>-1 would be everything to the right of that line.
y = -3 is a horizontal line that goes thru the y axis at -3, and y <= -3 is everything below that line
So you would have a quarter plane bounded at the top by the line y = -3 (and including this boundary) and bounded on the left by -1 (and not including that boundary)
Draw it and you'll see
2007-01-03 15:58:23
·
answer #1
·
answered by Joni DaNerd 6
·
2⤊
0⤋
substitute to y = x, then graph this yet particularly of making use of a solid line, draw the line as a dashed line (which shows all values on the line do not fulfill the inequality y < x). Then, because of the certainty the graph is going in the time of the muse, %. any ordered pair and attempt the ordered pair indoors the inequality fact. for celebration, shall we %. the ordered pair (4, -2), which, if graphed, could be 4 contraptions to the surprising on the x-axis, and a couple of contraptions decrease than (on a vertical line from x = 4) on the y-axix. Now, ask your self: Is -2 < 4? because of the certainty the respond is beneficial, all aspects on the surprising part of the graph (it truly is a diagonal line in the time of the muse with a slope of a million to a million (m = a million/a million, or a million) increasing from left to perfect), yet not such because of the certainty the aspects on the line, fulfill the inequality fact. As a attempt, %. the ordered pair (-2, 4). Then ask: Is 4 < -2? of direction not, so all aspects to the left of the graph do not fulfill the fact. As a make beneficial for those aspects on the line, merely %. an element. Say, (5, 5). Then ask: Is 5 < 5. of direction not, so all aspects on the line do not fulfill the fact. Your very very final answer is the intersection of all aspects of the two inequality statements.
2016-10-19 10:49:44
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
no-no-no-no-no-no (Leave pts up here OUT of graph.)
|
Y = -3 _________________________________
|
|
X = -1 All this region, including pts
| on y = -3, but leaving out
| pts on my "dotted vertical"
| line x = -1
|
2007-01-03 16:28:38
·
answer #4
·
answered by answerING 6
·
0⤊
0⤋