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3x^2=21,......-2x^2+1=0..............and 16/15x^2-1=0.....please show me how your work.........thanks!:)

2007-01-03 15:22:31 · 3 answers · asked by jenn 2 in Science & Mathematics Mathematics

3 answers

3x² = 21
x² = 7
x = ±√7

-2x² + 1 = 0
-2x² = -1
x² = 1/2
x = ±√(1/2) = ±√2/2

16/15x² - 1 = 0
16/15x² = 1
x² = 15/16
x = ±√(15/16) = ±√15/4

2007-01-03 17:03:18 · answer #1 · answered by Jim Burnell 6 · 0 0

I'm assuming youre solving for x.

1) 3x^2=21 (divide both sides by 3)
x^2=21/3 (simplify)
x^2=7 (take the square root of both sides)
x=sqrt 7


2) -2x^2+1 = 0 (subtracting 1 from both sides)
-2x^2 = -1 (divide by -2)
x^2=1/2 (take the square root of both sides)
x= sqrt 1/2 (i dont know if this is good enough for you class, so i'll take it down further)
x= (sqrt 1)/(sqrt 2) (now you simplify)
x= (sqrt 2)/2


3) 16/15x^2-1 = 0 (add 1 to both sides)
16/15x^2 = 1 (multiply both sides by 15)
16x^2 = 15 (divide both sides by 16)
x^2 = 15/16 (take the square root of both sides)
x = sqrt (15/16) (now you simplify if required by teacher)
x = (sqrt 15)/ (sqrt 16)
x = (sqrt 15)/4

I hope this is all the work you need...if not, message me at soccerman12uk@hotmail.com

2007-01-03 17:06:48 · answer #2 · answered by Tommy R 2 · 0 0

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2016-12-12 03:19:37 · answer #3 · answered by Anonymous · 0 0

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