quadratic equation with solutions of 4 and 7.?

15 ⤊

quadratic equation with solutions of 4 and 7.?

2007-01-03 14:47:48 · 4 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics

4 answers

x=4
x-4=0
x=7
x-7=0
(x-4)(x-7)=0 use FOIL
x^2-7x-4x+28=0
x^2-11x+28=0

2007-01-03 14:51:17 · answer #1 · answered by yupchagee 7 · 15⤊ 0⤋

As a matter of fact, since (x-4)(x-7) has zeros 4 and 7, so does the equation c(x-4)(x-7) for any nonzero constant c because when you set it to zero, you get

c(x-4)(x-7)=0, so you can divide both sides by c and get
(x-4)(x-7)=0 hence x=4 and x=7.

Happy New Year!

2007-01-03 17:52:18 · answer #2 · answered by Professor Maddie 4 · 0⤊ 0⤋

(x-4)(x-7)=0
=>x^2-11x+28=

2007-01-03 14:49:32 · answer #3 · answered by raj 7 · 0⤊ 0⤋

(x - 4)(x - 7)
x^2 - 7x - 4x + 28
x^2 - 11x + 28

2007-01-03 15:43:19 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋