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7 answers

You need to express this in form:
y=mx + b

2x - 3y = 6

-3y = -2x + 6

y = (2/3)x - 2

m= slope= 2/3

b= y-int= -2

Done!

2007-01-03 14:20:46 · answer #1 · answered by Jerry P 6 · 2 0

First: set the equation to "y" > subtract 2x from both sides >

2x - 3y = 6
2x - 2x - 3y = -2x + 6
- 3y = -2x + 6

Sec: keep "y" on one side (left) > divide both sides by -3 >

- 3y/-3 = -2x/-3 + 6/-3
y = 2x/3 - 2

Third: the slope is the fraction/number in front of the "x" variable and the y-intercept is the number/fraction after the "x" variable >

slope = 2/3
y-int = -2

2007-01-03 15:31:11 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0 0

surprising now, the line is in time-honored sort. it truly is greater handy to make certain the slope and y-intercept whilst the line is in y = mx + b sort. to transform the line from time-honored sort to y= mx + b sort: 2x - 3y = 6 3y = 2x - 6 y = (2/3)x - 2 The slope is m (that's stable in front of the x)- it truly is two/3. The y-intercept is -2 (that's represented via b). desire this facilitates :)

2016-10-19 10:42:36 · answer #3 · answered by ? 4 · 0 0

heres what you do:
move the 2x to the other side to get
-3y=6-2x

then divide both sides by -3
and you get

y=-2+2/3x

your slope is 2/3 and your y intercept is -2, you get that from setting X to zero and solving for Y. y=-2+2/3*0 = y=-2

hope this helped!

2007-01-03 14:25:38 · answer #4 · answered by Jordan P 1 · 1 0

2x - 3y = 6 subtract 2x from each side
-3y=-2x+6 divide by -3
y=2x/3-2 this is the slope intercept form
y=mx+b
the slope is m=2/3
the y-intercept is b=-2

2007-01-03 14:16:09 · answer #5 · answered by yupchagee 7 · 2 0

Subtract 2x from both sides:
-3y=-2x+6

Divide -3 from both sides:
y=2/3x-2
Slope:2/3
y-intercept:-2

2007-01-03 14:13:39 · answer #6 · answered by Anonymous · 1 0

Simply transpose.
-3y=-2x+6
y=2/3x - 2
Im only 6th grade so dont blame me if I get it wrong.
The one stuck with the x is the slope or the gradient.
The one after it is the y-intercept.

2007-01-03 15:46:20 · answer #7 · answered by ♫tweet75♫ 3 · 0 0

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