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I need to find the shortest distance from each side of the triangle (the sum of the distances from a certain point needs to be the shortest)!!

2007-01-03 14:00:39 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

As I understand the question, you want to find an interior point in the equilateral triangle such that the sum of the distances from each side is a minimum. And to know what that minimum is.

That point where distance is at a minimum is the center of the triangle.

Let

s = length of one side of the triangle
h = height of triangle

h = [(√3)/2]s

The distance from one side to the center point is (1/3)h. There are three such identical distances - one from each side. So the combined minimum distance is:

3(1/3)h = h = [(√3)/2]s

2007-01-03 14:27:39 · answer #1 · answered by Northstar 7 · 0 0

2/3 the distance from an angle to the opposite side, but this only works for equilateral triangles.

2007-01-03 22:12:23 · answer #2 · answered by Anna 3 · 0 0

It will be the point of intersection of the perpindicular bisectors.
The distance is s√3 /4 from each side where s is the length of a side.
The total distance is 3s√3 /4

2007-01-03 22:10:05 · answer #3 · answered by yupchagee 7 · 0 0

distance from midpoint to midpoint of each sides are shortest distance between two sides of equalateral triangle

2007-01-03 23:20:41 · answer #4 · answered by np200012 2 · 0 0

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