How do i simplifiy 25(25^(1/4))?
2007-01-03 13:37:50 · 7 answers · asked by Neil P 2 in Science & Mathematics ➔ Mathematics
25(25^(1/4))?
25x 25^1/4
5² x 5²^1/4
5² x 5¹/² = 5²+¹/² =
To sum the exponents 2 + 1/2 = 5/2
\/5^5 => sqrt of 5 power 5 = 25 time the root of 5 = 25\/5
The answer: 25\/5.
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2007-01-03 13:53:16 · answer #1 · answered by aeiou 7 · 3⤊ 0⤋
hint
your equation is in the form of
x^a * x^b = x ^ (a+b)
ok. here's the answer
25^1 * 25^(1/4) = 25^(1+1/4) = 25^1.25
2007-01-03 13:53:38 · answer #2 · answered by Dr W 7 · 1⤊ 0⤋
25^1/4 is the 4th root of 25 to the power 1, so it would be rt.5
Answer is 25 rt.5
2007-01-03 13:41:46 · answer #3 · answered by teekshi33 4 · 0⤊ 0⤋
Is it attainable that some thing did not get copied wisely. 5th root of seventy 5 (^5?seventy 5) = 2.371441 sq. root of seventy 5 (?seventy 5) = 5?3 there is not something that could desire to make the respond 25?3
2016-12-19 07:56:16 · answer #4 · answered by ? 4 · 0⤊ 0⤋
25(25^(1/4)) = (5^2)*((5^2)^0.25) = (5^2)*(5^0.5) = 5^(2+0.5) = 5^2.5
2007-01-03 13:49:11 · answer #5 · answered by The Alchemist 2 · 0⤊ 1⤋
25 = 5^2
so
5^2 ((5^(2*(1/4)))
=5^2 x 5^(0.5)
=5^(2+0.5)
=5^2.5
2007-01-03 13:39:58 · answer #6 · answered by Anonymous · 0⤊ 2⤋
25^ (5/4) or 25^(1.25)
2007-01-03 13:39:19 · answer #7 · answered by Anonymous · 0⤊ 2⤋