This is math. please help?

Question

find four consecutive intergers whose sum is 130.

Find the measure of the third angle.
(z-30)*, z*

*degree sign

please explain
thanks

Answer 1

1) 4 consec numbers if you devide by 4 you will get the middle score. 130/4 = 32.5. Two nombers must be below this and two above it. You get 31, 32, 33, 34

2) I assume the angles are in a triangle. The angles in a triangle add to 180*. If we call the third angle x then
x = 180 - ( (z-30) + z )
x = 180 - (2z - 30)
x = 210 -2z

With the information you have given that is the best I can do!

Answer 2

find four consecutive intergers whose sum is 130= n + (n+1) + (n+2) + (n+3) = 4n+6
So 130=4n+6... can you complete the rest?

Find the measure of the third angle.
(z-30)*, z*
So it's a traingle! And we all know that trangles have 180 degrees! So we know that z + (z-30) + x = 180. Let's take away the first two angles.
180 - z - (z-30)= z + (z-30) + x - z - (z-30)
Can you figure it out now??

Answer 3

Let's name the first of the four consecutive integers x. The next three would then be x + 1, x + 2, and x + 3.
x + (x + 1) + (x + 2) + (x + 3) = 130
4x + 6 = 130
4x = 124
x = 31
Therefore, your four integers must be 31, 32, 33, and 34.

In triangles, the angle measures add up to 180 degrees.
If you name your third angle x...
(z - 30) + z + x = 180
You want to know what x equals, so solve for x:
2z - 30 + x = 180
2z + x = 210
x = 210 - 2z

Hope I helped!
10 points best answer?

Answer 4

31+32+33+34 = 130. The second part doesn't make sense sorry.

Answer 5

x= 1st number, (x+1) = 2nd number, (x+2) = 3rd number, (x+3) = 4th number

so x + (x+1) + (x+2) + (x+3) = 130

you'll have to do the rest.

the next question is sort of similar

Answer 6

32.5 (130/4) the first one

Answer 7

f=mc2