47/3
2007-01-03 13:18:15
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answer #1
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answered by Denise T 3
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Use Pythagoras' Theorem:
c^2 = a^2 + b^2
=> 28^2 = 19^2 + b^2
=> 784 = 361 + b^2
=> b^2 = 423
=> b = sqrt(423) = sqrt (9.47) = 3.sqrt(47).
2007-01-03 21:16:22
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answer #2
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answered by Scarlet Manuka 7
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w = â(28^2-19^2) = â423 = 3â47 = 20.57
2007-01-03 21:18:09
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answer #3
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answered by sahsjing 7
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If you're requiring that the answer be one of your 3 choices, then you're out of luck; of the first 6 answers
5 are essentially equivalent. The first answer is precise
3 x sq-rt 47; 4 of the remaining 5 are either similar or are approximations to this exact answer.
2007-01-03 21:24:30
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answer #4
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answered by answerING 6
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It's a right-angled traingle
Diagonal is the hypotenuse
Width = (28^2-19^2)^0.5
2007-01-03 21:17:15
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answer #5
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answered by no man 2
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use the pythagorean theorem: sqrt(28*28-19*19), which is just a litlte more than 20.
None of the answers above fits this.
2007-01-03 21:16:27
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answer #6
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answered by firefly 6
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the diagonal is the hypotenuse
a^2+b^2=c^2
19^2+b^2=28^2
361+b^2=784
b^2=423
b=20.57
2007-01-03 21:19:06
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answer #7
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answered by 7
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