2y+1/3 - y+4/5 = 7?

Question

how the hell do you do this??

(2y+1)/3 - (y+4)/5 = 7?

Answer 1

first thing you need to do is group the y terms and the numbers together so
y+1/3+4/5=7
if you multiply by 15 (the lowest number that 3 and 5 will both go into)
15y+5+12=105
15y+17=105
15y=88
y=88/15=5 and 13/15

Answer 2

You have to group like terms: all the bits with y on the left, all the bits without y on the right. Remember that when you move something from one side to the other, you have to change the sign from - to + or from + to -.

2y + 1/3 - y + 4/5 = 7
=> 2y - y = 7 - 1/3 - 4/5
=> (2-1) y = 7 - 1/3 - 4/5
=> y = 7 - 1/3 - 4/5.

Now we have to put the fractions on the right over a common denominator; the lowest common denominator of 3 and 5 is 15.
=> y = (7*15 - 1*5 - 4*3) / 15
= (105 - 5 - 12) / 15
= 88 / 15
= 5 13/15 if you prefer mixed fractions.

Answer 3

2y - y = 7 - 1/3 -4/5
y = 105/15 - 5/15 - 12/15
y = 88/15

Answer 4

{y:y=88/15}