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1) K2Cr2O7 + HCl >>>> KCl + CrCl3 + Cl2 + H2O

2) Bi2S3 + HNO3 >>>> Bi (NO3)3 + NO + S + H2O

3) HgS + HCl + HNO3 >>>> HgCl2 + NO + S + H2O

2007-01-03 12:18:00 · 2 answers · asked by truckin_90 2 in Science & Mathematics Chemistry

2 answers

1) Start by balancing the oxygen, and then balance the potassium and the chromium. Once you do that, the only thing left unbalanced is the chlorine, and you can fix that with one coefficient. You should get this:

K2Cr2O7 + 14HCl >>>> 2KCl + 2CrCl3 + 3Cl2 + 7H2O

2) I gave this one a shot, but I didn't get anything. Good luck!

3) This one I got. I would start by getting the chlorine to balance, then the hydrogen, then the oxygen, and keep on going. Your coefficients will be 3s, a 6, a 4, and 2s.

2007-01-03 12:46:29 · answer #1 · answered by AskerOfQuestions 3 · 0 0

I got number 1. If I get the others, I'll post em.

K2Cr2O7 + 14HCl >>> 2KCl + 2CrCl3 + 3 Cl2 + 7 H2O

I am pretty sure that numbers 2 and three don't work.

2. Notice the HNO3 and the Bi(NO3)3 + NO + H2O. I can find no common multiple of all 4 of those

3. I can't find a common multiple between the HNO3 and the NO + H2O

Sorry that I couldn't help very much.

2007-01-03 13:04:16 · answer #2 · answered by mttcttrll@snet.net 3 · 0 0

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