math help?

Question

2y2-9y+4/8y-2y2
please show how to do this

Answer 1

The expression is unclear. Is this a single fraction? Use () or[ ], to clarify. My guess is this is a single fraction. Factor the expression & simplify.

Numerator:
2y^2 - 9y + 4 = (2y - 1)(y - 4)

Denominator:
8y - 2y^2 = -2y(y - 4)

One simplified form is (2y - 1) / (-2y)
[ the common factors (y - 4) cancel]

Answer 2

The task is to simplify the expression. You do that by factoring the numerator and the denominator in hopes of finding a term that is common to both of the. Since this is a homework problem, you can be pretty sure there is a common factor.

Lets start with the denominator since its simpler. I like to have the squared term first so, rewrite it as
-2y2 + 8y

If you stare at that long enough you will see that you can divide both terms by 2y

so, the factored form is (-y + 4) (2y)

just to double check see that -y times 2y = -2y2 and 4 times 2y = 8y the two terms of the original denominator.

ok...now since this is a homework problem, we can guess that the numerator can be factored so that one of the terms is (-y + 4)... so, the question becomes, what do we need to mulitply (-y + 4) by to get 2y2-9y+4. The first term of the mystery is easy. It has to be -2y ...so, now we have

(-y + 4) (-2y + ?)

since the 4 and the -2y multiply to give -8y, the question mark and the -y have to multiply to give -y so that we can get the -9y that is in the original numerator. That means the question mark has to be 1

(-y + 4) (-2y + 1) is the factored form of the numberator

(-y + 4) (2y) is the factored form of the denominator

the (-y + 4) 's cancel each other out

so the answer is (-2y + 1) / (2y)

you can check your answer by picking some values for y and pluging them into the original form of the fraction and the factored/simplified form

Answer 3

It'd be better in this forum to use parentheses to better show what you're doing and ^ for the exponents. I'm going to rewrite your question the way I think you meant it:

(2y^2 - 9y + 4)/(8y - 2y^2)

You need to factor your numerator first. That's the tricky part. For me, at least, it's not obvious what the two factors are, so let me work it out for you step by step the way I think it through:

I can't factor out a number, so I'm going to have a setup of something like:
(y+__)(y+__)
But I have 2y^2, which means that one of those will be 2y (of course, on paper, you don't have to do this line after line, you can just add in the 2 where you need it):

(2y+__)(y+__)

But I notice that I have -9y but my final number is positive.That means that both factors involve -.

(2y-__)(y-__)

Now to figure out what those constants are, the really tricky part. To get 4 for the final constant in the original expression, I will need to have 1 and 4, 2 and 2 or 4 and 1. I notice that if I put it 1 and 4, I'll end up having my -9y.

(2y-1)(y-4)--let me check by FOIL: 2y^2 -8y - y + 4 Good.

Now the denominator:

The denominator is actually rather easy, but I'm going to reorder it because I just prefer working with my y^2's first, even if you NEVER put a - variable first when you have other terms in your expression as a final answer:

-2y^2 + 8y

Both terms have 2 as a factor as well as y. But I'm going to pull out -2y so that my first term is positive:

-2y(y-4)

So now I put the two together (actually, on paper it already would be):

(2y-1)(y-4)
--------------
-2y (y-4)

The y-4's cancel each other, so I'm left with

(2y-1)/-2y or (-2y-1)/2y

Answer 4

2y^2-9y+4/8y-2y^2=-9y+1/2y=-18/2y+y=-9y+y=-8y

1st step i did was cancel out the 2y^2 and - 2y^2
2nd i simplified 4/8y to 1/2y
3rd i took the L.C.M. of -9y and 1/2y
4th i simplified -18/2y and got -9y
then i got the answer -8y because i subtracted 1 from 9, keeping the y, and putting a negative sign becuz 9 is bigger than 1...so we put the sign of the bigger number

Answer 5

4y-9y+1/2y-4y~here 2y2 is the same as saying 2 times y times two and all you have to do is multiply 2 by 2 to simplify it and 4/8 is the same as 1/2

-8 1/2y~4y and -4y cancel each other out when you combine like terms and all that's left gets added together

was y squared?

Answer 6

2y^2 - 9y + 4
------------------
8y - 2y^2

= -9y + 4 - 1
--------------
8 y

the numerator & denominator both have 2y^2
think of 2y^2 as 1
so 1/ -1 = -1

= -9y + 3
---------
8y

simplify

= 8y (-9y+3)

get rid of the denominator by multiplying (opposite of dividing)

= -72y + 24y

distribute the 8y

= -48y

simplify






^^ hope that helps