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2x+5k=6k2-3kx-6 solve for x
this is a algebraic fraction but i can't find a way to get x by itself.

2007-01-03 11:42:44 · 2 answers · asked by alyssa p 1 in Science & Mathematics Mathematics

2 answers

to further reduce from Helmut's answer

X=2K-3

Start by subtracting5K from both sides and adding 3KX to both sides. Factor out for x then reduce the fraction yielding

X=2K-3

2007-01-03 12:11:03 · answer #1 · answered by bob d 2 · 0 0

2x + 5k = 6k^2 - 3kx - 6
2x + 3kx = 6k^2 - 5k - 6
x(2 + 3k) = 6k^2 - 5k - 6
x = (6k^2 - 5k - 6)/(3k + 2)
x = (2k - 3)

2007-01-03 19:54:35 · answer #2 · answered by Helmut 7 · 0 0

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