math help?

0 ⤊

25c+15d/50c2+30d2
algebraic fractions

2007-01-03 11:40:30 · 3 answers · asked by alyssa p 1 in Science & Mathematics ➔ Mathematics

3 answers

Assuming the directions are to simplify.
Factor top and bottom: 5(5c+3d)/10(5c^2+3d^2)
Your final would be (5c+3d)/2(5c^2+3d^2) since the binomial oin the denominator does not factor further.

2007-01-03 11:45:44 · answer #1 · answered by dwobbit 2 · 0⤊ 0⤋

(25c + 15d) / (50c^2 + 30d^2)

The first thing to do is factor the top and bottom.

5(5c + 3d) / 10(5c^2 + 3d^2)

Now, the 5 and 10 can be reduced like any fraction.

(5c + 3d) / 2(5c^2 + 3d^2)

This can't be factored any further.

2007-01-03 19:44:51 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋

huh????????????????

2007-01-03 19:47:42 · answer #3 · answered by smart won 2 · 0⤊ 0⤋