Lowest common multiple!!!?

Question

Lowest common multiple of

2x^4-2x^2y^2 and 4x^5+8x^4y+4x^3y^2 and 6x^2+6xy

Answer 1

It may be easer to see if you factor as much individually first:

2x^4-2x^2 y^2 = 2x^2(x^2-y^2)
4x^5+8x^4y+4x^3y^2 = 4x^3(x^2+2xy+y^2)
6x^2+6xy=6x(x+y)

LCM is always the like factors times the nonlike factors:

Like factors: 2x
Non like: (x^2-y^2), 2x^2, (x^2+2xy+y^2), 3, (x+y)

Answer 2

The Least Common Multiple (LCM) of the numbers
2x^4-2x^2y^2 and 4x^5+8x^4y+4x
is
4
because 4 is the smallest number that all of the numbers divide into evenly.

Tip- go to webmath.com

Answer 3

Dan has the right method, but he didn't completely factor the first two terms.

When he factored the first term, he included (x^2 - y^2), which can be factored into (x+y)(x-y).

The second term he factored included (x^2 + 2xy + y^2), which can be factored into (x+y)(x+y).

Once you correct those two factorizations, you'll see that (x+y) is also a common factor for all 3 terms (as are 2 and x), so it should be included ONCE in the LCM, not 3 times. Note, however, that since (x+y) appears twice in the second term's factorization, it will still have to be includes TWICE in the LCM.

Hope that's enough clues to get you through this.

Answer 4

LCM(2x^4-2x²y² and 4x^5+8x^4y+4x³y² and 6x²+6xy) =
2x²(x²-y²); 4x^4(x+2y+xy²+);6x(x+y) =
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