Please show your working out.
Please help ;]
2007-01-03 10:21:34 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There are 3 prizes.
2007-01-03 10:27:35 · update #1
Please use the way where you do non replacement problems if yoo do know..
2007-01-03 10:30:36 · update #2
The probability of not getting the first prize is 497/500. After the winning ticket is removed there are 499 tickets remaining so the probability of not getting the second prize is 496/499. Same thing happens for the third, 495/498. The probablility of all three happening is the product of the three probabilities: (497/500)(496/499)(495/498).
2007-01-03 10:50:11 · answer #1 · answered by statboy76 2 · 0⤊ 0⤋
If she has 3 tickets, and 500 are sold, then there are 497 tickets that can be chosen for her to lose. Therefore, the probability that she will not win a prize is 497/500.
2007-01-03 10:26:13 · answer #2 · answered by Nick R 4 · 0⤊ 0⤋
If she has 3 tickets, and 500 are bought, then there are 497 tickets which may be chosen for her to lose. for this reason, the prospect that she would be waiting to now no longer win a prize is 497/500.
2016-10-29 22:27:39 · answer #3 · answered by ? 4 · 0⤊ 0⤋
the probability is simply the ratio of tickets bought to tickets sold, unless there is more than one drawing (which is not stated in the question). Thus 3/500 is the probability of winning and thus 497/500 is the probability of losing.
2007-01-03 10:27:05 · answer #4 · answered by ? 3 · 0⤊ 0⤋
She has 3 probabilities out of 500, because she only bought THREE TICKETS.
She has a probability of 497 out of 500 not to win.
3 bought tickets - 500 tickets total
3 probabilities of prize.
497 not bought tickets (by Margaret) - 500 tickets total.
497 probabilities of no prize.
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99.4% chance of not winning. Divide 497 by 500.
2007-01-03 10:27:42 · answer #5 · answered by cristaline 2 · 0⤊ 0⤋
Always ask this: Of all the possible outcomes, how many satisfy the requirement I'm talking about? In this case, 497 of them do. So the probability is 497 out of 500. Convert that to a percent and ... voila!
2007-01-03 10:25:14 · answer #6 · answered by All hat 7 · 0⤊ 0⤋
It is impossible to tell: one needs to know the number of prizes. If there are 498 prizes, Margaret is certain to win at least one of them. If there is only one prize, the odds that she will not win it are 497/500.
2007-01-03 10:26:28 · answer #7 · answered by Anonymous · 0⤊ 0⤋
447 of 500 chance of reciveing the win in the raffle
2007-01-03 10:30:13 · answer #8 · answered by Anonymous · 0⤊ 0⤋
she has a 3/500 chance of winning, so that equals a 497/500 chance of not winning.
2007-01-03 10:23:34 · answer #9 · answered by sWtnsiMpLe 3 · 0⤊ 0⤋
99.4% chance of not winning. 497 divided by 500.
2007-01-03 10:26:07 · answer #10 · answered by John G 4 · 0⤊ 0⤋