It's been killing me to know
Gaara? Rock Lee? WHO WINS THE BATTLE?
2007-01-03 10:07:28 · 15 answers · asked by Paris C 1 in Entertainment & Music ➔ Comics & Animation
gaara because rock lee was not able to control his taijutsu technique
2007-01-03 10:10:09 · answer #1 · answered by god_of_war 4 · 0⤊ 0⤋
Gaara Vs Rock Lee
2016-10-04 08:14:20 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Gaara wins and almost destroys Rock Lee.
2007-01-04 05:07:03 · answer #3 · answered by God R 3 · 0⤊ 0⤋
Gaara because lee used a reverse lotus and it made him extremely vulnerable to Gaara's attacks and then when Gaara was just about to kill Lee
Gai sensei stopped Gaara by telling Gaara that he loved Lee
and yeah Gaara left lee alone and tada!!
thats it
watch the anime!
it was really sad
when he screamed when Gaara did the desert coffin thing on him it was really painful to watch
2007-01-03 10:41:01 · answer #4 · answered by tenshi 2 · 2⤊ 0⤋
Gaara wins
2007-01-03 11:44:26 · answer #5 · answered by GOTHIC_SANNIN 4 · 0⤊ 0⤋
Rock Lee did well at the start, but in the end he got his *** kicked by Gaara. Poor Rock Lee... :(
2007-01-03 10:15:21 · answer #6 · answered by Meg 2 · 0⤊ 0⤋
Gaara won the battle.
2007-01-04 03:43:01 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Lee wins in terms of determination. He was unconcsious and he stood up to fight more. Now that's dedication. Too bad Gaara won in terms of actually winning.
2007-01-03 15:56:53 · answer #8 · answered by TheShankmaster 4 · 0⤊ 0⤋
Gaara.
2007-01-03 10:12:51 · answer #9 · answered by Anonymous · 0⤊ 0⤋
i think that rock is his first then lee as his second because the author was aiming for a sort of bruce lee type of thing and also most people call some people by there last name or lee is just a nick name but also in japan they think differently so meaning that rock lee could be his full first name and he doesnt have a last name and sasme with uzumaki naruto they come like a pair hope you figure out soon have a happy new year!!!!!!!!!!
2016-03-17 22:59:05 · answer #10 · answered by Anonymous · 0⤊ 0⤋