Limit in math question : lim {(2/л).Arctan x} when x→∞?

Question

cant? if u can plz give the shortest answer

Answer 1

Edit: didn't realize that was a pi symbol.

lim ([2/pi] * arctan(x))
x -> infinity

Is equal to

lim (2arctan(x)/pi)
n -> infinity

But as x gets very large, arctan actually converges to a value (pi/2). Therefore, we get

2(pi/2)/pi = 2pi/2pi = 1

Answer 2

Since lim x-> pi/2 of tan x approaches infinity, I think
lim x -> infinity of arctan x is pi/2. So your limit is 2/pi * pi/2 = 1.

Answer 3

plug in the decimal to inverse tangent and see if the limit exists within the given bound of infinity.