Find the slope of any line perpendicular to the line through points (0, 5) and
(3, 4).
2007-01-03 06:31:32 · 5 answers · asked by CelticMoonGoddess 2 in Science & Mathematics ➔ Mathematics
First find the slope of the line through the points given. Slope is rise over run, or difference in the y coordinates over difference in the x coordinates:
m = (y1 - y2) / (x1 - x2), where m is the slope
Let's say (x1, y1) = (0,5) and (x2, y2) = (3,4). Then we have:
m = (5 - 4) / (0 - 3) = 1/ (-3) = - 1/3
Now when lines are perpendicular, their slopes are negative reciprocals. So the slope of a line perpendicular to our given line is the negative reciprocal of -1/3, which is 3. (Negative reciprocal means "turn the fraction part upside down and multiple by -1.")
2007-01-03 06:41:32 · answer #1 · answered by Lola 3 · 0⤊ 0⤋
The slope of any line is ∆y/∆x
The slople of any line perpendicular to a given line is -∆x/∆y
-∆x/∆y = -(3-0)/(4-5) = 3
2007-01-03 06:39:13 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
The slope of this line is (5-4)/(0-3) = -1/3, so the slope of the perpendicular line is 3 (because the product of the slopes of two perpendicular lines is -1).
2007-01-03 06:36:02 · answer #3 · answered by Anonymous · 1⤊ 0⤋
the equation of the orginal line is: y= -1/3x+5 so a perpendicular line would have y= 1/3X+5
2007-01-03 06:37:52 · answer #4 · answered by novae2 3 · 0⤊ 1⤋
extremely tough situation query on to google it could help
2014-07-21 01:03:14 · answer #5 · answered by Anonymous · 0⤊ 0⤋