Find the slope of any line perpendicular to the line through points (0, 5) and?

Question

Find the slope of any line perpendicular to the line through points (0, 5) and
(3, 4).

Answer 1

Hi, iroc did a good job up until he said the slope of the perp. line is the negative of the slope of the first line.

GONG!

The slope of a perpendicular line is the negative 'inverse' of the first line.

So, if the first line is y = -1/3x + 5, then the slope of any line perpindicular to it is:

===>3 and the eq. for any line perp. is y = 3x +c

Answer 2

Hi:

First off the bat is find the slope of those points by using the following formula :

slope = (Y2-Y1)/ (x2-X1)

So:

Slope = (4-5) / (3-0)

Slope = -1/3

Slope = -1/3

And -1/3(x) +b = y to find the y intercept when x= 0

since one of the point as x = 0 which give us the y intercept
( 0,5) being 5

So
y = -1/3x + 5

Since the Perpendicular line to this is the negative number of the slope of this line So :

Then 1/3x + 5 = y is the Perpendicular line of ( 0,5) and (3,4)

Answer 3

The slope formula for the line through any two points (x,y) is:

rise/run = (y2 - y1) / (x2 - x1)

The slope of the perpendicular is simply the negative reciprocal:

-run/rise= - (x2 - x1)/(y2 - y1)

Answer 4

complex situation lookup on google or bing it could help