I want to balance a chemical reaction and I need help.?

Question

Cu + HNO3 -------> Cu(NO3)2 + NO + H2O

Answer 1

6Cu + 12(HNO3)-------> 6(Cu(NO3)2) + 4(NO) + 8(H2O)
I'm fairly certain this the answer you want. This was done in my head, so I can't be completely certain.

Answer 2

I do these using algebra.
(Incidentally, Nick R's answer is close, but his H's don't balance. Also, all his coefficients are even, so he should have divided by 2.)

Let the coefficient of Cu (on the left side) be x. Then the coefficient of Cu(NO3)2 has to be x also, since that's the only place where Cu appears on the right side.

Let the coefficient of H2O (on the right side) be y. Then the coefficient of HNO3 on the left side must be 2y, since you need two molecules of HNO3 to produce the 2 H's for each molecule of H2O. (These are the only molecules that involve hydrogen.)

Now use z for the coefficient of NO and start finding relationships among x, y, and z that will give you the same amount of N and O on the two sides. (N and O appear multiple times on the right side, so they are the elements that complicate things.)

Example: For N, you have 2y = 2x + z

In the end, you won't have fixed values for x and y, but you'll have a RATIO that you can use to choose values of x and y, and then solve for z. For example, if you find that the ratio x/y is 2/3, then you can set x = 2 and y = 3 (or x = 4 and y = 6).

Good luck!

Answer 3

wAHT YOU WILL DO IS TO GET THE COEFFICEINT NUMBER AND BALNCE IT TO THE REACTED COMPUNDS YOU CAN GET IT JUST TRY...DO YOU FOLLOW?