4a+10and7a+7 the number are inside a parallelogram?

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4a+10and7a+7 the number are inside a parallelogram?

2007-01-02 14:12:26 · 2 answers · asked by sexy cee 1 in Science & Mathematics ➔ Mathematics

2 answers

I'm going to assume that you mean that these the measures of the two different angles of a parallelogram.

Therefore the sum of the two angles must be 180:

4a + 10 + 7a + 7 = 180
11a + 17 = 180
11a = 163
a = 14.8

So one angle is 4(14.8) + 10 = 69.3, and the other is 7(14.8) + 7 = 110.7

2007-01-02 17:35:59 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋

This question is not clear.

Do you mean inside where the angles should be?

Guido

2007-01-02 22:19:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋