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The "long method" that I'm saying is:
f(x) = [(x)^(5/3)]
f(x + h) = ?
f(x + h) - f(x) = ?
[f(x + h) - f(x)] / h = ?
limit of {[f(x + h) - f(x)] / h} as h approaches 0 = ?

f(x) = [(x)^(4/3)]
f(x + h) = ?
f(x + h) - f(x) = ?
[f(x + h) - f(x)] / h = ?
limit of {[f(x + h) - f(x)] / h} as h approaches 0 = ?

2007-01-02 14:11:05 · 2 answers · asked by dreamcatcher 2 in Science & Mathematics Mathematics

2 answers

Why use the long method?

The answers are:

1. F'(x) = 5/3x^2/3

2. F'(x) = 4/3x^1/3

2007-01-03 09:11:59 · answer #1 · answered by Anonymous · 0 0

You must really want the answer as you put this on twice.

2007-01-02 22:17:15 · answer #2 · answered by ? 6 · 0 0

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