1. 1/ h+1 + 2/3 = 2h+5/ h-1
2. 3m-2/ 2m(squared) - 5m -3 - 2/ 2m+1 = 4/ m-3
3. Find a quadratic equation of the form ax(squared) + bx +c =0
a. 3/2 , -4
b. 3 + radical 5 , 3 - radical 5
2007-01-02 14:05:11 · 3 answers · asked by cfishot 2 in Education & Reference ➔ Homework Help
i only know the first one...sorry i couldn't help with the rest.
In order to solve a fractional equation, the denominators must be the same. so u find the common denominator which is 3h+3. (u can multiply the denominators to get common denom.) Then u multiply the 1st fraction by 3 and u get 3/h+3, the 2nd fraction by h+1, and u get 2h+2/3h+3, then the 3rd fraction by 3, and u get 6h+15/3h+3. then u can multiply the whole equation by 3h+3 because they have that in common. Now ur left with 3+2h+2=6h+15, which then equal 2h+5=6h+15, then u can just solve for h by getting like terms on one side...ur answer should be -5/2=h. good luck!
2007-01-02 15:24:27 · answer #1 · answered by lattekiwi 1 · 0⤊ 0⤋
I know how to do number 2:
factor 2m^2-5m-3 which equals (2m+1)(m-3)
multiply whole equation by the common denominator [(2m+1)(m-3)] to get rid of the denominator:
(3m-2)-2(m-3)=4(2m+1)
3m-2-2m+6=8m+4
m+4=8m+4
m=0
check your work and you'll see it works!
2007-01-02 21:17:04 · answer #2 · answered by bobburns11 1 · 0⤊ 0⤋
cliffsnotes.com
2007-01-02 14:06:34 · answer #3 · answered by Isabela 5 · 0⤊ 0⤋