2007-01-02 13:05:59 · 5 answers · asked by Sally s 1 in Science & Mathematics ➔ Mathematics
2√(-50) - 3√(-8) = 2i√50 - 3i√8
= 2i√(2*25) - 3i√(2*4)
= 5*2i√2 - 2*3i√2
= 10i√2 - 6i√2 = 4i√2
2007-01-02 13:11:30 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
2
2007-01-02 21:06:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
4(sqrt -2)
2007-01-02 21:13:20 · answer #3 · answered by pstrbrc1 2 · 0⤊ 0⤋
2sqrt(-50) - 3sqrt(-8)
2sqrt(-25 * 2) - 3sqrt(-4 * 2)
(2 * (-5i or +5i))sqrt(2) - (3 * (2i or -2i))sqrt(2)
(10i * sqrt(2)) - (6i * sqrt(2))
±(10i + 6i)sqrt(2) or ±(10i - 6i)sqrt(2)
±16i * sqrt(2) or ±4i * sqrt(2)
2007-01-02 23:18:54 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
2 rad -50 - 3 rad -8
2 rad [(-1)(25)(2)] - 3 rad [(-1)(4)(2)]
2 (i) (5) rad 2 - 3 (i) (2) rad 2
10 i rad 2 - 6 i rad 2
4 i rad 2
2007-01-02 21:11:47 · answer #5 · answered by danjlil_43515 4 · 0⤊ 0⤋