if i made 5267 individual items and had 44 mistakes,what is my accracy percentage
2007-01-02 13:05:53 · 7 answers · asked by pops1954 1 in Science & Mathematics ➔ Mathematics
Total Item : 5,267
Number of Mistakes = 44
Therefore, the number of Correct item is 5,267-44=5,223
Accuracy Percentage is Correct Item/Total Item x 100
ie 5,223/5,267 x 100 = 99.17% (round to 2 decimal place)
Alternatively, you can find out the mistake percentage and then use it to less from 100%
44/5,267x 100% = 0.84%
To find accurancy percentage is 100%-Mistake percentagei.e. 100-0.84 = 99.16% (slight difference is due to rounding of decimal place)
2007-01-02 17:56:17 · answer #1 · answered by cls22cls 2 · 0⤊ 0⤋
You made 5267 total items, and 44 mistakes. So you made 5267 - 44 = 5223 correctly. Now divide them and convert to a percent:
(5223 / 5267) * 100 = 99.16%
2007-01-02 21:37:35 · answer #2 · answered by j 4 · 0⤊ 0⤋
5267 = 100%
44 = x
x = 44 times 100 divided by 5267 = .83539
subtract: 100 - .83539 = 99.16 %
2007-01-03 02:24:17 · answer #3 · answered by David C 2 · 0⤊ 0⤋
Divide the number of items by the number of mistakes.
5267 / 44 = 119.7
So, for approximately every 120th item, one is an error.
1/119.7
2007-01-02 21:10:07 · answer #4 · answered by Privratnik 5 · 0⤊ 0⤋
5223/5267 * 100
2007-01-02 21:07:52 · answer #5 · answered by jackie 1 · 0⤊ 0⤋
99.16%
2007-01-02 21:09:22 · answer #6 · answered by Anonymous · 0⤊ 1⤋
i dunno
2007-01-02 21:07:02 · answer #7 · answered by Anonymous · 0⤊ 1⤋