is a^2+b^2=c^2 or no a+b+=c
2007-01-02 12:13:22 · 6 answers · asked by Chris FIGggggg 1 in Science & Mathematics ➔ Mathematics
Three numbers form a Pythagorean triple if the *square* of the two *smaller* numbers add to be the *square* of the *largest* number.
Put your numbers in order: 7, 24, 25
Now square each one:
7² = 49
24² = 576
25² = 625
Notice:
7² + 24² = 25²
49 + 576 = 625
So 7, 24 and 25 do form a Pythagorean triple.
Here's a list of Pythagorean triples under 100:
(3, 4, 5)
(5, 12, 13)
(7, 24, 25) <--- Here's yours
(8, 15, 17)
(9, 40, 41)
(11, 60, 61)
(12, 35, 37)
(13, 84, 85)
(16, 63, 65)
(20, 21, 29)
(28, 45, 53)
(33, 56, 65)
(36, 77, 85)
(39, 80, 89)
(48, 55, 73)
(65, 72, 97)
2007-01-02 12:21:54 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
It is
a² = b² +c² ==> a = 25; b = 24; c = 7
25² = 24² + 7²
625 = 576 + 49
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2007-01-02 20:17:18 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
Yes 24² = 576 and 7² = 49.
576 + 49 = 625 = 25².
2007-01-02 20:19:26 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
7^2 = 49
24^12 = 576
49 + 576 = 625
sqrt(625) = 25
Yes, it is a pythagorean triple
2007-01-02 20:17:04 · answer #4 · answered by Tom :: Athier than Thou 6 · 1⤊ 0⤋
24^2=576
7^2=49
25^2=625
figure out
2007-01-02 20:17:29 · answer #5 · answered by raj 7 · 0⤊ 0⤋
yes
2007-01-02 20:20:17 · answer #6 · answered by operalph 4 · 0⤊ 0⤋