what is the width of a rectangle fi the diagonal is 28 and the length is 19?

Question

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Answer 1

Imagine your rectangle with a diagonal line drawn from one corner to another. This would create a triangle for which you could apply Pythageron's theroem, that being that the square of the longest side of a right triangle is equal to the sum of the squares of the other two sides and then solve for the missing side algebraicly. Something like:

c^2 = a^2 + b^2
28^2 = 19^2 + b^2
784 = 361 + b^2
b^2 = 784 -361
b^2 = 423
b = sq root of 423 or
b = 20.567 approximately

Answer 2

The diagonal will make this a right triangle. So, 19^2+x^2=28^2
361 + x^2 = 784
x ^2 = 423
x = square root of 423

Note: 4+2+3 = 9, so it is divisible by 9

x = square root of (9*47)
x = 3 square root of 47

47 is prime, so this is the final answer.

Answer 3

Use our old friend the Pythagorean theorem:
let x be the width, then by old Pythag
28^2 = 19^2 + x^2
x^2 = 28^2 -19^2 = 784 - 361 = 423
x = sqr(423) ~ 20.56

Answer 4

20.567
Use the Pythagorean theorem to figure it out. Take the square root of the diagonal squared minus the length squared.
28 squared = 784
19 squared = 361
Difference = 423
Square root = 20.567

Answer 5

28 squared = 19 squared + x squared

therefore x squared = 28 squared - 19 squared

x squared = 9 squared

the root of x is the answer = 9

Answer 6

28^2 - 19^2 = width^2

784 - 361 = w^2 = 423

w = 20.57

Answer 7

sqrt(28^2 - 19^2) which is about 20 and a half..
If you draw it, you can see that you can use the pythagorean theorem.

Answer 8

Pythagorean theorem....

c = 28
a = 19
b = width

c^2 = a^2 + b^2
(28)^2 = (19)^2 + b^2
423 = b^2
b = 20.6

Answer 9

it will be rt(28^2-19^2)

Answer 10

all you need to use is Pythagoras theorem: you'll get 20.57