geometry
2007-01-02 11:40:41 · 7 answers · asked by Chris FIGggggg 1 in Science & Mathematics ➔ Mathematics
No, they do not.
The hypotenuse is always the longest side of a right triangle, so that would be 19. We then need to see if 5^2 + 13^2 =?= 19^2
25 + 169 =?= 361
194 =/= 361
2007-01-02 11:43:00 · answer #1 · answered by Anonymous · 1⤊ 0⤋
No, because 5² =25
13² = 169
25 + 169 = 194.
But 19^2 = 361.
As a matter of fact, these cannot even be the
sides of a triangle, because 5 + 13 < 19.
The sum of any 2 sides of a triangle must be
greater than the third.
2007-01-02 20:42:49 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
No; and, in fact, you don't even need to do any squaring to know this. The triangle inequality states that any side of a triangle MUST be less than the sum of the other two, and in this case 19 is not less than 5 + 13. Therefore, it's not even a triangle, let alone a pythagorean triple.
2007-01-02 20:12:12 · answer #3 · answered by operalph 4 · 2⤊ 0⤋
nope
5^2 + 13^2 =
25 + 169 =
194
19^2 = 361
2007-01-02 19:45:03 · answer #4 · answered by lana_dog 2 · 0⤊ 0⤋
â(5^2+13^2+19^2)=â(25+169+361)=â(555)=23.558437978779492926264680186639
No.
2007-01-02 19:44:08 · answer #5 · answered by yupchagee 7 · 0⤊ 1⤋
no
3,4,5.
6,8,10.
9,12,15.............etc
2007-01-02 19:47:33 · answer #6 · answered by Billy T 5 · 0⤊ 0⤋
no.
2007-01-02 19:43:35 · answer #7 · answered by Susie 2 · 0⤊ 0⤋