The number of dimes is x.
The number of nickles is x - 5.
The number of quarters is x + 3
Therefore x + (x - 5) + (x + 3) = 52
3x - 2 = 52
3x = 54
x = 18
So Sal has 18 dimes, 21 (x + 3) quarters, and 13 (x - 5) nickles for a total of 52 (18 + 21 + 13) coins.
2007-01-02 11:45:25
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answer #1
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answered by Anonymous
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21 quarters, 18 dimes and 13 nickels
2007-01-02 19:52:38
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answer #2
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answered by Lucy S 1
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21 quarters - 18 dimes -13 nickels
2007-01-02 19:48:25
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answer #3
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answered by Ret68 6
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Quarters + Dimes + Nickles = 52
Quarters = Dimes + 3 (D+3)
Dimes = (D)
Nickles = Dimes - 5 (D-5)
Restate the formula
(D+3)+(D)+(D-5)=52
3D-2=52
3D=54
D=18
Q=21
N=13
Total Dimes = 18
Total Quarters = 21
Total Nickles = 13
Total Coins = 52
2007-01-02 20:02:16
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answer #4
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answered by The Answer Man 5
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Quarters = x+3
Nickels = x - 5
Dimes = x
total coins = 52 coins
equation:
X + 3 + X - 5 + X = 52
combine like terms & simplifies to:
3X - 2 = 52
Add 2 to both sides...
simplifies to
3X = 54
Divide by coefficient of X ...(3)
X = 18 dimes
2007-01-02 19:48:14
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answer #5
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answered by Rmprrmbouncer 5
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18 dimes
2007-01-02 19:48:27
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answer #6
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answered by spiritcrossfuse999 2
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It is 18 dimes, 21 quarters, and 13 nickels... i am so smart!!!! S-M-R-T!!!
2007-01-02 19:52:30
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answer #7
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answered by Anonymous
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18 dimes.....21 quarters....13 nickles. Algebra question.
2007-01-02 19:50:11
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answer #8
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answered by chrislewi 2
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Just have Sal take his jar to the coinstar machine and they will tell him.
2007-01-02 19:40:25
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answer #9
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answered by sixcannonballs 5
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Sal has more money than me!;
2007-01-02 20:27:59
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answer #10
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answered by huggz 7
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