b^2-2b+3b-6 ( that is "b" to the 2nd power) how would you factor this using the distributive property.

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b^2-2b+3b-6 ( that is "b" to the 2nd power) how would you factor this using the distributive property.

I have no Idea. Its 9th grade algebra. I need Help IM LOST HELP ME!!!! lolz

2007-01-02 09:55:05 · 3 answers · asked by PandaLuvr 1 in Science & Mathematics ➔ Mathematics

3 answers

b² - 2b + 3b - 6

Start by taking the first two terms and factoring out a common b:
b(b - 2) + 3b - 6

Then take the last two terms and factor out a common 3:
b(b - 2) + 3(b - 2)

Now you have a common b - 2 to factor out:
(b + 3)(b - 2)

There's your answer

2007-01-02 10:00:12 · answer #1 · answered by Puzzling 7 · 2⤊ 0⤋

b^2-2b+3b-6
= b(b-2) + 3(b-2)
= (b+3)(b-2)

2007-01-02 17:57:07 · answer #2 · answered by sahsjing 7 · 1⤊ 0⤋

(b-2)(b+3)

2007-01-02 17:59:14 · answer #3 · answered by well thts it...... 3 · 1⤊ 0⤋