Empirical formula of a chemical compund just can be computed if you are given experimental data.
As you know the molecular formula (you gave us above) you do not need the empirical one.
Good luck!
2007-01-02 09:44:59
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answer #1
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answered by CHESSLARUS 7
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Glycine Formula
2016-10-06 04:17:38
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answer #2
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answered by jaspal 4
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That IS the empirical formula for glycine. The empirical formula for any compound is the one in which the subscripts are the smallest possible. So, since you can't have anything lower than 1 as a subscript (for N in glycine) this is as reduced as it can be, so that is the empirical formula.
2007-01-02 09:44:09
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answer #3
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answered by hcbiochem 7
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Glycine Molecular Formula
2016-12-11 19:15:24
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answer #4
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answered by ? 4
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I agree with hcbiochem's answer. An empirical formula is the lowest whole number ratio between the elements in the compound; C2H5NO2 already is in simplest terms. As for CH2O, there's no nitrogen in the formula, so it can't be the empirical formula for glycine, because glycine contains nitrogen.
2007-01-02 09:48:40
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answer #5
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answered by AskerOfQuestions 3
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This Site Might Help You.
RE:
What is the empirical formula for C2H5NO2 (Glycine)?
2015-08-08 19:02:11
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answer #6
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answered by Anonymous
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c2h5no2 is the empirical formula as you cannot divide the subscripts by a common factor
2007-01-02 09:58:00
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answer #7
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answered by dundledee 2
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Take those percentages and treat them as masses. Convert them to moles using the molar masses, therefore: 32.00 g / (12.011 g/mol) 6.72 g / (1.0079 g/mol) 18.66 g/ (14.007 g/mol) 42.63 g / (16 g/mol) Once you calculate those, divide each of them by the lowest of the numbers (it will be the one for nitrogen). You should get C2H5NO2.
2016-03-12 21:20:27
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answer #8
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answered by Anonymous
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C2H5NO2, I guess (you have forgot NO2 group in your further definition!).
All other, more detailed formulas like CH3-CH2.....are structural ones.
2007-01-02 09:57:11
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answer #9
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answered by silberstein_9 3
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(C2H5NO2)v where v is a positive non-zero integer 1, 2, 3, ...
2007-01-02 10:42:24
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answer #10
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answered by Dimos F 4
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