How much heat does it take to heat 12g of ice at -6 degrees C to 25 degrees C water?

Question

could i have the answer in Joules please? and also could you tell me hoe to do it?

Answer 1

The amount of energy used E (in Joules), used to heat a substance of mass M (in grams) by T (degrees kelvin or Celsius) is:

E = sMT, where s is the Specific Heat of the substance

For water, the specific heat is:

ice = 2.114 J/g/K
liquid = 4.1813 J/g/K

So the energy used to heat the 12g of ice from -6 to 0 degrees =

2.114*12*6 = 152 J

And the water from 0 to 25 degrees

4.1813*12*25 = 1254 J

Now, we are not done yet as it takes energy to MELT the ice. This is called the Latent Heat - the energy required for a material to undergo a "phase change" - in this case from ice(solid) to water (liquid).

For ice the Latent heat for melting is 335 J/g.

Therefore melting 12g of ice requires 335*12 J = 4020 J

So the total energy required is 1406 + 4020 J = 5426 J

Answer 2

1. Heat the ice to the melting point. Calculate the number of joules necessary from information on *specific heat* provided in your textbook.

2. Calculate the heat necessary for the phase transition from solid to liquid. This happens at 0 degrees C.

3. Calculate the heat needed to heat the water from 0 to 25 degrees.

Add results from 1 + 2 + 3.

Answer 3

1 joule heats 1g by 1 degree
12 joules heats 12g by 1 degree
372 joules will heat 12g of ice from -6 to 25 degrees

Answer 4

You must do this in 2 steps....need to use heat of fusion of ice to change ice to liquid, then use 4.184J/(1g*1C) for total degree change

The heat of fusion of water is 79.72 calories per gram or 335.5 joules per gram.

1. 12g * (335.5J/g) =
2. 31C * 12g * 4.184J/(1g*1C)=

Add these two numbers...Sorry I don't have a calculator.

Answer 5

372 cal or 1556 J, but this assumes that the specific heat of ice is the same as for water.

The equation is Q = m x dT x C; where Q is heat in J, m is the mass of water, dT is the change in temperature, and C is the specific heat of water (1 cal/g/degC or 4.184 J/g/degC).