(4LO-O*O)/(6/v*9*1/(e*e)*1/9)?

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(4LO-OO)/(6/v9*1/(ee)1/9)?

2007-01-02 06:21:06 · 2 answers · asked by meron b 1 in Science & Mathematics ➔ Mathematics

2 answers

Are you trying to simplify this?
(4LO-O*O) is O(4L-O)

the denominator is 6/v*9*1/(e*e)*1/9 and immediately we can see that 9 and 1/9 cancel, so we have
6/[v*e*e]

so the entire equation simplifies, but not very much, to
O(4L-O)*(v*e^2)/6

2007-01-02 07:25:37 · answer #1 · answered by firefly 6 · 0⤊ 0⤋

My opinion coincides with yours. Just do it!

2007-01-02 09:16:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋