what is 3x + y = 0, than graph the equation?

Answer 1

3x + y = 0

3x + y = 0 + 3x

y = 3x

- - - - - - - -

3x + y = 0

3x + y - y = 0 - y

3x = - y

3x / 3 = - y / 3

x = - y / 3

- - - - - - -s-

Answer 2

The best way is to solve for y so the equation will be in y = mx + b form, which is the best form for me. In this form, you automatically know the slope (m) and the y-intercept (b). So to solve for y:

3x + y = 0
y = -3x

(You subtract 3x from both sides of the equation to isolate y). To graph it, you can place a point at the y-intercept, which we know is 0, because there is no value for b in the equation (y = mx +b .... y = -3x + 0 ....we just drop the 0 because it is unnecessary to show it, and it is understood that it is there). So on the y-axis, place a point at 0, which is the point (0, 0).

To graph the line, you need at least one other point. You can find this in two ways: you can use the slope, or you can plug a number into the equation. Using the slope is easier. Since the equation is in the form y = mx +b, we know that the slope is -3. The slope is defined as the change in y over the change in x. Since -3 is not a fraction, we can put it over 1 to make it a fraction. Now we have (-3)/1. Now we just go to our original point that we already put on the line at (0, 0). From here you just go down 3 (because the 3 in your fraction is the change in y. You go down instead of up because 3 is negative) and then you go to the right 1 (because 1 is the change in x. You go to the right because it is positive, if it is negative, you go to the left). This will leave you at the point (1, -3). Now all you have to do use use a straight edge to connect the lines. Be sure to extend the line beyond the points and put arrows on the ends to indicate that the line extends to infinity. The line should be sloping up and to the left since the slope is negative. If it was positive, your line would be sloping up and to the right.

Ok, the other way to find another point is a little more work, but it is just as easy. All you have to do is plug any random number into your equation. For ease of use, you can stick with small numbers like 1 or 0. Therefore, we will set x = 1. Plug 1 into the equation and you now have y = (-3)(1) and we solve that to get y = -3. That means your new point is (1, -3) and you can connect this to your original point at the origin, just like last time. This would work if you plugged in any number. If you plugged in 0, you would get (0, 0), if you plugged in 2, you would get (2, -6), etc. Any point you get will be on the line.

I hope this helped, and now you know how to do it for the future :)

Answer 3

3x +y = 0 is the equation of a line.
To graph it, find the x and y intercept. That's what x equals when y equals zero, and what y equals when x equals zero.
An easy way to figure that out is this trick I learned in my algebra class. To find the x-intercept, remove the y from the equation, and solve. In this case, the equation becomes 3x = 0. So, x = zero. Do the same for y.

Since both the x and y intercept are zero, you cannot figure out how to graph the line just from that info. A way to graph it is to change the equation to slope-intercept form. Subtract 3x from each side, so that you get y = -3x + 0. In this equation, the integer after the x is the y-intercept (in this case,zero). And the coefficient of x is the slope. So, the line passes through point (0,0), and has a slope of -3.

Answer 4

Subtract 3x from both sides:
y=-3x

It's a straight line graph and just plug in numbers for x to get the y-values.

Answer 5

3x+y=0 is the same as y=-3x+0 or y=-3x.
The format is y=ax+b. a=slope b=y-intercept.
Since the y-intercept is 0, the line automaticlly passes through (0,0).
Subsitute x for some values. The answer is y.
-3(-2)=6
-3(2)=-6
The line will pass through (-2,6), (0,0), and (2,-6).

Answer 6

get the equation in y= form:

y=-3x

there is no constant, so start the line on the origin (0,0)
the slope is -3/1. to find the next point, go down 3 and to the right one (or up 3 and to the left one). then just connect the points to get the line.

yeah, i'm not so good at explaining, lol. did that make sense?

Answer 7

Graph of a line running through points
(-1/3, 1) to (0,0) to (1/3, -1)