what are the exact values of x in the domain 0<x<2pi for tan(3pi-x)=1???

Answer 1

tan(y) = 1 <=> y=(π/4)+kπ, k is an integer

so,
tan(3π-x)=1
<=>
3π-x = (π/4)+kπ (^ 0
that means, that if (π/4)+kπ, then k = {0,1,2}, so there are 3 possible "x"

{
3π-x = π/4
v
3π-x = π+π/4
v
3π-x = 2π+π/4
} <=>

{
x = 11/4π <- out of range
v
x = 7/4π
v
x=3/4π

final answer: x = 7/4π or 3/4π

Answer 2

3 pi - x = pi/4 + k pi. x= 3 pi / 4 or 7 pi /4

Answer 3

45/7^>>9u7-(%>''(o)1/2)x35>**pl0./;.,[[[7]]]=+456y8(&*().