2007-01-02 04:17:28 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(5a+2)(3a-1)=
15a^2-5a+6a-2=
15a^2+a-2
2007-01-02 04:23:03 · answer #1 · answered by toeysgirl 2 · 2⤊ 0⤋
Just multiply every term by every other term and add them.
(5a)(3a) + (5a)(-1) + (2)(3a) + (2)(-1)
15a^2 - 5a + 6a - 2
15a^+a-2
2007-01-02 04:21:44 · answer #2 · answered by Barkley Hound 7 · 2⤊ 0⤋
...
(5a + 2)3a - 1)
= 15a^2 + a - 2
...
2007-01-02 04:23:38 · answer #3 · answered by Jon 3 · 1⤊ 0⤋
15a^2-5a+6a-2
15a^2+a-2 ANS.
2007-01-02 04:20:56 · answer #4 · answered by aminnyus 2 · 2⤊ 0⤋
(5a + 2)(3a - 1) =
15a² + 6a - 5a - 2 =
15a² + a - 2
- - - - - - - -s-
2007-01-02 06:11:46 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋
15a2 - 5a + 6a - 2 = 0
15a2 + a - 2 = 0
2007-01-02 04:24:02 · answer #6 · answered by marashhab2002000 2 · 1⤊ 0⤋
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2016-11-25 22:36:26 · answer #7 · answered by ? 4 · 0⤊ 0⤋
(5a+2)(3a-1)=
15a^+6a-5a-2=
15a^+a-2
2007-01-02 05:59:06 · answer #8 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
15a^2+a-2
2007-01-02 04:18:44 · answer #9 · answered by raj 7 · 2⤊ 0⤋
15a^2+a-2 or 225a+a-2
Just answer worked out
2007-01-02 04:24:54 · answer #10 · answered by Anonymous · 0⤊ 0⤋