If you were on the moon, How fast would you have to throw a baseball for it to leave the gravity of the moon?

Answer 1

TimmyD's got it.

2.4 km/s = 8,640 km/h = 5,400 mi/h

Quite a fast ball.

Bullets? nope.

Muzzle velocities range from below 0.33 km/s for some pistols to more than 1.8 km/s for tank guns firing kinetic energy penetrator ammunition. The latter velocity is close to the limit achievable with chemical propellants. (Wikipedia)

Answer 2

Moon escape velocity = 2.4 km/s

In physics, for a given gravitational field and a given position, the escape velocity is the minimum speed an object without propulsion, at that position, needs to have to move away indefinitely from the source of the field, as opposed to falling back or staying in an orbit within a bounded distance from the source.

Answer 3

Well, you'd have to find that out for Earth first, which I have no idea, then divide that by 6, because the Moon's gravity is that 1/6ths of the gravity here on Earth.