factor this expression?

Question

cd + de

Answer 1

cd+de = d(c+e)

You take out the 'common factor', in other words the thing that features in both expressions. When this is put in front of the brackets it means you add c and e together and then times that number by d, which is the same as multiplying c and d and adding d multiplied by e.

For example, think of 2x8 + 3x2
This is 16 + 6 = 22

which is the same as:

2(8+3)
This is 2x11 = 22

Answer 2

i attempted this stunt: flow the three from the front end to the back, giving x^2 + 5x -6. This tells us that we desire 2 numbers, whose difference is 5 and product is 6. of course, a million and six qualify. So, in case you progression the three back the place it started, you land up with a million and 2, so which you have (3x -a million)(x + 2). If no longer something works, you could continuously equate the expression to 0, resolve the end result with the quadratic formula, and if the roots are r1 and r2, the expression has aspects (x - r1)(x - r2). That performs despite if the roots are complicated, regardless of the undeniable fact that during that case one in many situations says that the expression is key.

Answer 3

SInce the two variables have d in common, you can take it out of the equation

cd + de
=
d(c + d)

Answer 4

Factor out d:
d(c+e)

Answer 5

...

Find a common factor, in this case it's d

d(c + e)

...

Answer 6

cd + de
= d(c+e)

Answer 7

code and decode

Answer 8

cd + de

d(c + e)

- - - - - s-

Answer 9

GCF:
d(c+e)

Answer 10

d(c+e)