2007-01-02 03:07:41 · 13 answers · asked by josh w 1 in Science & Mathematics ➔ Mathematics
3v(v-3)-w(v-3)
(3v-w)(v-3)
2007-01-02 03:31:04 · answer #1 · answered by Anonymous · 4⤊ 0⤋
3v^2 - 9v -wv +3w
group common terms
= (3v^2 - 9v) - (wv - 3w)
= 3v(v - 3) - (wv - 3w)
= 3v(v-3) - w(v-3)
factor out (v-3)
= (v-3)(3v - w)
2007-01-02 12:44:55 · answer #2 · answered by Anonymous · 1⤊ 0⤋
3v^2-9v-wv+3w = 0
3v^2-9v = wv-3w
3v(v-3) = w(v-3)
(3v-w)(v-3) = 0
2007-01-02 11:12:14 · answer #3 · answered by emma 6 · 5⤊ 1⤋
3v^2 - 9v - wv + 3w
= 3v(v - 3) - w(v-3)
=(v -3)(3v -w)
2007-01-02 11:13:00 · answer #4 · answered by Sheen 4 · 4⤊ 1⤋
3v^2-9v-wv+3w =(3v^2-9v)-(wv-3w)
= 3v(v-3)-w(v-3)
=(v-3)(3v-w)
2007-01-02 22:22:51 · answer #5 · answered by ousep 1 · 0⤊ 0⤋
(3v²-9v)-(wv+3w) =
3v(v-3)-w(v -3)=
(3v-w)(v-3)
>::
2007-01-04 09:18:56 · answer #6 · answered by aeiou 7 · 0⤊ 0⤋
(3v-w) (v-3)
factor by grouping and then factor out the common (v-3) from that result...
2007-01-02 11:16:37 · answer #7 · answered by kingarthurdare 2 · 4⤊ 1⤋
3v^2-9v-wv+3w
(v-3)(3v-w)
2007-01-02 11:12:48 · answer #8 · answered by SHIBZ 2 · 4⤊ 1⤋
...
3v^2 - 9v - wv + 3w
= 3v(v - 3) - w(v - 3)
= (3v - w)(v - 3)
...
2007-01-02 11:19:21 · answer #9 · answered by Jon 3 · 0⤊ 4⤋
3v^2-wv-9v+3w
v(3v-w) -3(3v-w)
(v-3)(3v-w)
2007-01-02 11:11:55 · answer #10 · answered by bh 2 · 5⤊ 1⤋