2007-01-02 02:59:28 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You have to use the grouping method.
First rearrange the terms.
ac+ad + bc+bd
Factor out an "a" from the first two terms and factor out a "b" from the last two terms leaving you with:
a(c+d)+b(c+d)
Now both terms have a (c+d) in common so you can factor it out.
(a+b)(c+d)
2007-01-02 03:03:38 · answer #1 · answered by wizard of ozma 3 · 1⤊ 0⤋
ac+bd+bc+ad+eg+fh+fg+eh?
2007-01-02 04:20:24 · answer #2 · answered by marashhab2002000 2 · 0⤊ 0⤋
ac+bd+bc+ad
(a+b)(c+d)
2007-01-02 03:19:02 · answer #3 · answered by SHIBZ 2 · 0⤊ 0⤋
ac + bd + + bc + ad
ac + bc + bd + ad
c(a + b) + d( b + a)
(c + d(a + b)
- - - - - -s-
2007-01-02 03:07:52 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
Try grouping them together:
ac+bc+ad+bd
c(a+b)+d(a+b)
(a+b)(c+d)
2007-01-02 03:04:46 · answer #5 · answered by david stern/mitch kupchak basher 2 · 0⤊ 0⤋
a(c+d) + b(c+d)
= (a+b)(c+d)
2007-01-02 03:04:00 · answer #6 · answered by martina_ie 3 · 0⤊ 0⤋
(a+b)(c+d)
2007-01-02 03:10:39 · answer #7 · answered by saltpepper1956 1 · 0⤊ 0⤋
(a+b)(c+d)
2007-01-02 03:02:07 · answer #8 · answered by robcraine 4 · 0⤊ 1⤋
...
a(c + d) + b(c + d)
= (c + d)(a + b)
....
2007-01-02 03:01:51 · answer #9 · answered by Jon 3 · 0⤊ 0⤋