2007-01-02 02:58:38 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The factorization is (rs - 2)(r^2s + 2).
Group like this:
(r^3s^2 + 2rs) + (-2r^2s - 4)
Factor rs out of the first part and -2 out of the second part:
rs(r^2s + 2) - 2(r^2s + 2)
Now apply the distributive property:
(rs - 2)(r^2s + 2).
2007-01-02 03:01:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1
2007-01-02 02:59:45 · answer #2 · answered by Anonymous · 0⤊ 2⤋
r³s² - 2rs(r+1) - 4
rs(r²s - 2(r+1)) - 4
2007-01-02 03:02:07 · answer #3 · answered by Dave 6 · 0⤊ 0⤋
r^3s^2-2r^2s+2rs-4
(rs-2)(sr^2+2)
2007-01-02 03:21:14 · answer #4 · answered by SHIBZ 2 · 0⤊ 0⤋
(r^2s+2) (rs-2)
2007-01-02 03:04:43 · answer #5 · answered by Brad D 2 · 0⤊ 0⤋
What's the matter, Mike -- you wasted the whole vacation and now your homework is due???
Do your own work!
2007-01-02 03:00:31 · answer #6 · answered by Anonymous · 1⤊ 1⤋
set u = (k+1)^2 , v = 2i , i = root(-1) u^2-v^2 = (u-v)(u+v)
2016-05-23 06:14:48 · answer #7 · answered by Anonymous · 0⤊ 0⤋
No, and nobody can make me.
2007-01-02 03:00:18 · answer #8 · answered by Munya Says: DUH! 7 · 1⤊ 1⤋