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5Fe2+ 8H+ + MnO4 - = 5FE3+ + Mn2+ + 4H2O

the question is asking me determine the % of iron II and iron III in a mixture containing both, where i am given 200cm3 of a solution containing 1.3g of iron ions(Fe 2+ Fe 3+) using potassium magnanete

(here is where i get confuse) You may assume that each of the 2 ions of is present to at least 30% by mass (doesnt this contradict the question?)

also, i tried calculating it out via those normal calculas titration method but i cant go any further unless if i know the vol. of potassium maganate used to titrate the iron solution.

Can i just make it up what vol. is required to titrate the iron solution with the potassium maganate??

2007-01-02 02:50:13 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

To begin with, the name of the oxidizing compound is permanganate (MnO4-).

From the balanced equation you can see that the MnO4- only reacts with the Fe(II) and not the Fe(III):

5 Fe+2 + 8 H+ + MnO4- --> 5 Fe+3 + Mn+2 + 4 H2O

To calculate how much of the Iron is +2 or +3, you need the data telling you how much (in moles) of the MnO4- was used in the titration. This could be calculated if you knew the molar concentration and volume of the MnO4- solution.

One mole of MnO4- would react with 5 moles of Fe+2. You could calculate the moles of Fe+2 that was oxidized.

Knowing the 1.3 grams of Iron was in the 200 cc of Iron solution. you could then calculate the total moles of Iron. Subtract the moles of Fe+2 to get the moles of Fe+3 in the original sample.

2007-01-06 05:41:16 · answer #1 · answered by Richard 7 · 20 0

You can guess if you want. But, you would need to actually need to do the experiment. Without the experimental data you cannot proceed with the calculations to find the %'s. Guessing would give you an inacurate answer (unless you guessed right of course).

2007-01-03 18:07:10 · answer #2 · answered by Jfquiring 2 · 0 0

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2016-11-25 22:25:49 · answer #3 · answered by Anonymous · 0 0

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