5Fe2+ 8H+ + MnO4 - = 5FE3+ + Mn2+ + 4H2O
the question is asking me determine the % of iron II and iron III in a mixture containing both, where i am given 200cm3 of a solution containing 1.3g of iron ions(Fe 2+ Fe 3+) using potassium magnanete
(here is where i get confuse) You may assume that each of the 2 ions of is present to at least 30% by mass (doesnt this contradict the question?)
also, i tried calculating it out via those normal calculas titration method but i cant go any further unless if i know the vol. of potassium maganate used to titrate the iron solution.
Can i just make it up what vol. is required to titrate the iron solution with the potassium maganate??
2007-01-02
02:50:13
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3 answers
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asked by
Anonymous
in
Science & Mathematics
➔ Chemistry