The cost of 10 oranges and 5 apples is 3.35. Twenty-four oranges and twelve apples cost 8.04. Find the cost of each orange and each apple.
I have to use the methods of comparison or elimination, or substitution.
Every time I try it is always gets cancelled out. These are the equations I get out of the word problem:
R = oranges and A = Apples
10R + 5A = 3.35
24R + 12A = 8.04
Maybe someone can show me the procedure and how to get the answer. It would be very appreciated. Thank you ahead of time.
2007-01-02 02:41:46 · 7 answers · asked by Jazz 2 in Science & Mathematics ➔ Mathematics
unfortunately you cant work this out as the 2nd is just 2.4 times the 1st so they are basically the same equation
2007-01-02 02:50:55 · answer #1 · answered by Ivanhoe Fats 6 · 1⤊ 0⤋
The two equiations you have come up with from the question are actually the same. The second one is the first one multiplied by 2.4. Therefore, you actually have one equation and 2 unknowns. I suggest re-reading the question carefully. If you find this is the only imformation available, you must solve this by trial and error (subbing in reandom values...ie. Oranges are $0.25, therefore apples must be $0.17)
2007-01-02 10:52:41 · answer #2 · answered by Adam T 1 · 1⤊ 0⤋
I've never been good at following procedure on math problems. I always have weird ways of figuring them out. But if oranges are .25 and apples cost .17 it works out. I'm not sure how to show the work on it properly, but that's the answer.
10 x .25 = $2.50
5 x .17 = $0.85
---------
$3.35
24 x .25 = $6.00
12 x .17 = $2.04
---------
$8.04
Hope that helps!
2007-01-02 10:54:55 · answer #3 · answered by yardbird_24 2 · 0⤊ 1⤋
well..I don't know if you realized this but the cost of apples and oranges is the same so I think that all you need to do is take 3.35 divided by 15 and you get about .22 (.22333333333333 to be exact) and so it would be about 22 cents each..I hope I helped and I think that is the right answer..Good Luck!!
2007-01-02 10:51:32 · answer #4 · answered by Anonymous · 0⤊ 1⤋
10R + 5A = 3.35
Divide both sides by 5
2R + A = 0.67 (1)
24R + 12A = 8.04
Divide both sides by 12
2R + A = 0.67 (2)
You are dealing with same equation as is clear from (1) and (2).
Still you can have values like a chart
A = 0.07, B = 0.30
A = 0.17, B = 0.25
and so on
2007-01-02 10:50:57 · answer #5 · answered by Sheen 4 · 1⤊ 0⤋
i did the work out and i have the same problem as you. it van be determined that the problem has no solution.
2007-01-02 10:48:42 · answer #6 · answered by blah 4 · 0⤊ 0⤋
i solved this problem but i encounter the same problem as yours. i think there is no answer in this problem.
2007-01-02 10:59:05 · answer #7 · answered by Lee 1 · 0⤊ 0⤋