2007-01-02 02:16:17 · 7 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
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The graph is a circle. The centre is at the origin (0,0) and the radius is the square root of 3.
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2007-01-02 02:28:56 · answer #1 · answered by Jon 3 · 0⤊ 1⤋
The graph is a circle with center at the origin.
Its radius is â3.
Note that the coefficients of the x² and y² terms
are equal and both have the same sign. That
always shows you that this type of equation
represents a circle.
2007-01-02 10:24:38 · answer #2 · answered by steiner1745 7 · 0⤊ 1⤋
Generalized equation of a circle
(x-a)^2 + (y-b)^2 = R^2
(a, b) >> coordinate of centre, R = radius of circle
Given:
a = 0, b = 0 and R = sqrt(3)
So it is a circle.
2007-01-02 10:35:57 · answer #3 · answered by Sheen 4 · 0⤊ 0⤋
It's a circle centered on the origin. It's radius is the square root of 3.
2007-01-02 10:21:57 · answer #4 · answered by Steve S 3 · 1⤊ 1⤋
It is absolutely circle. This kind of equations can be thought that all of x and y values have the same distance from the origin which is square root of 3
2007-01-02 10:21:15 · answer #5 · answered by ZeberCet 2 · 1⤊ 1⤋
its a circle with a center at (0,0) with a radius square root of 3.
so to graph it.
take your pencil, and put a dot at (0, 0) to indicate the middle.center of the circle
and since the radius is the square root of three. add/subtract square root of three to the top side, bottom side, left side, and right side.
in other words
the top should be (square root of 3,0)
the bottom should be (-square root of 3,0)
the left should be (0,-square root of 3)
and finally the right side should be (0,square root of 3)
hope dat helped
2007-01-02 10:25:46 · answer #6 · answered by Sultan Cartman 5 · 0⤊ 1⤋
I believe it's a circle
2007-01-02 10:17:30 · answer #7 · answered by Michael784 2 · 1⤊ 1⤋