graph x+12>y?

Answer 1

there is not one graph
there exist infinite number of graphs for this
it can exist in discontinous form also
such graph is not fixed
there exist infinite graphs

Answer 2

x + 12 > y

What you want to do is put it in a form "similar" to y = mx + b (with the exception being the = sign, of course)

x + 12 > y

-y > -x - 12

Multiplying both sides of the inequality by (-1) flips the inequality sign, so

y < x + 12

At this point, what we do is graph the line y = x + 12, and we're either going to shade above or below the line.

To determine where we shade, pick the point (0,0), and plug in x=0 and y=0 into the inequality. Do we get a true or false statement? If we get a true statement, shade the region that includes (0,0); if not, shade the other region.

If x = 0 and y = 0, and y < x + 12, then
0 < 0 + 12 ?
0 < 12? This is a true statement.

So you would shade BELOW the line y = x + 12. Make sure to keep y = x + 12 a "dashed" line to indicate that the inequality does not include it.

If you have y <= x + 12 (less than or equal to), it would be a solid line. But since it's y < x + 12, the line itself is not included.

Answer 3

Draw the line y=x+12
Then all the Halp Plane above the line is your graph