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2007-01-01 23:56:59 · 8 answers · asked by porcha b 1 in Science & Mathematics Mathematics

8 answers

-2/3x < 14

Now, when you say -2/3x, do you mean -2/(3x), or (-2/3)x? It's a bit ambiguous. I'll just solve both.

-2/(3x) < 14

Bring the 14 over, to get
-2/(3x) - 14 < 0

-2(1/(3x) + 7) < 0

-2[1/(3x) + 21x/(3x)] < 0
-2[ (1 + 21x)/(3x)] < 0

Dividing both sides by -2, this changes the inequality sign.

(1 + 21x) / (3x) > 0

To solve for this inequality, we note that our critical values are what makes the left hand side equal to 0 or undefined. In our case, it's x = -1/21 and x = 0

By testing each interval, you'll find out that we get a true inequality at
(-infinity, -1/21) U (0, infinity)

***
If, however, you meant
(-2/3)x < 14

Then, we multiply both sides by (-3/2), switching the inequality sign in the process to get

x > 14(-3/2)
x > -21

Therefore, our solution set is x > -21.

2007-01-02 00:03:17 · answer #1 · answered by Puggy 7 · 0 0

If you mean -(2/3)x < 14

-(2/3)x < 14
(2/3)x > -14
x > -14*3/2
So x > -21
So x is any number between -21 and infininty

If you mean -2/(3x) < 14
-2/(3x) < 14
-2 < 42x
So x > -0.047619
So x is any number between -0.047619 and infinity

I hope that answers your question

2007-01-02 08:06:45 · answer #2 · answered by Ahmed A 2 · 0 0

x>21

2007-01-02 08:27:53 · answer #3 · answered by gjmb1960 7 · 0 0

x>-21

2007-01-02 08:25:33 · answer #4 · answered by JAMES 4 · 0 0

-2/3x < 14
Solution is: (0,∞) ∪ (-∞,-(1/21))

(-2/3)x < 14
Solution is: (-21,∞)

2007-01-02 08:14:25 · answer #5 · answered by igor_wilk 2 · 0 0

-2/3x < 14
2/3x > -14
x > -21

2007-01-02 08:20:04 · answer #6 · answered by Tom :: Athier than Thou 6 · 0 0

take the constant to the right hand side. The sign will change as it is a negative constant.

x>21 is the answer.

2007-01-02 08:05:34 · answer #7 · answered by IN PURSUIT OF WISDOM 2 · 0 1

Hi my friend,

Answer is x can be anything equal to or less than -20.

GoodLuck!

2007-01-02 07:59:54 · answer #8 · answered by Yvonne Mystic 4 · 0 2

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