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If a person guessed a one-sided die correct ten times, then four different colored marbles correct ten times, and then a two-sided coin correct ten times, what would be the mathematical probability of that person being correct consecutively? This is a total of thirty correct consecutive guesses. Please show your work.

2007-01-01 21:41:08 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

P = [(1/1)(1/4)(1/2)]^10 =
1/8^10 =
1/2^30 =
9.3132*10^-10

2007-01-01 22:06:30 · answer #1 · answered by Helmut 7 · 0 0

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