Math Problem?

Question

A says to B. I am 5 times as old as you are when I was as old as you are now.Sum of their present ages is 64. Find present ages.

Answer 1

Let n be the number of years that have passed.
Let A be age of A now.
Let B be age of B now.

'n' years ago, A's age was B's age then.
A - n = B

Current ages sum to 64.
A + B = 64

A is 5 times as old B was 'n' years ago.
A = 5(B - n)

Three equations, three unknowns...
To solve start by solving for one of the variables in terms of the others:
n = A - B

Now substitute n into the last equation:
A = 5(B - (A-B))
A = 5(B - A + B)
A = 5(2B - A)
A = 10B - 5A
6A = 10B
3A = 5B

Now solve for one of the variables (e.g. B)
B = (3/5)A

And substitute into the second equation:
A + (3/5)A = 64
(5/5)A + (3/5)A = 64
(8/5)A = 64

Now multiply both sides by 5/8:
A = 64(5/8)
A = 40

And solve for B:
40 + B = 64
B = 64 - 40
B = 24

Note: Sixteen years ago, A was 24 (same as B now) and B was 8. That makes A five times as old as B was then.

So A is 40 years old and B is 24 years old.

Answer 2

I am not completely sure about the wording, but this is my interpretation. People A and B are currently a and b years old respectively.

The second sentence says: a = 5*(b - (a-b)) which simplified says a = (5/3)b. Plugging this into the equation a+b=64 (from the third sentence gives: (8/3)b = 64, which implies that B is currently 24 years old and A is currently 40 years old.

Answer 3

b is age of B
a is age of A

when a was as old as b is now , a is 5 times older

a=5b
a+b=64

solve this and you have the answer

Answer 4

sorry ,to dumb to answer this one!!!!!